If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4.9x^2-9.6x-49.4=0
a = 4.9; b = -9.6; c = -49.4;
Δ = b2-4ac
Δ = -9.62-4·4.9·(-49.4)
Δ = 1060.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.6)-\sqrt{1060.4}}{2*4.9}=\frac{9.6-\sqrt{1060.4}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.6)+\sqrt{1060.4}}{2*4.9}=\frac{9.6+\sqrt{1060.4}}{9.8} $
| 3x-2/7=7-2x-1/4 | | -t=26 | | 3x-2/7=7-2x | | k-k^2-27=0 | | -4=-2(x+7) | | 2(-3x+2)=-14 | | 4.9x^2-19.4x-74.1=0 | | 7x−1=2x+3 | | 2÷3c+1=1÷6c-2 | | 1/1-x/6=x/3+1/2 | | 6/4x=-7/8 | | 8x^2-8x-6=-8x | | 8x²-8x-6=-8x | | (4x-6)(2x+1)=-8x | | n/8+1/2=-3.1/2 | | (4/x)+0.5x=5 | | 4n-23/4=-222/3 | | 10*(2x-1)^4=0 | | 3x+12=4x+20 | | 10(2x-1)^4=0 | | 5(2x-1)^4(2)=0 | | 1.3^m=1.25 | | x/3=(x+2)/5 | | 2x+6/3=4(x-2) | | 4x+4=2x−6 | | 2^x+1×16^2x+1=3 | | 2^(x+1)×16^(2x+1)=3 | | 120=1/2(3x+2)(x+2) | | 0=9-(1/3q) | | -0.1x^2+4x-30=21 | | 10(k-2)=12k | | -0.1x^2+4x-30=30 |